Article Type : Research Article
Authors : Orlov S
Keywords : Theory of vortex gravitation
Investigated directly proportional dependence of the energy end mass of a physical object on the strength of the vortex gravitation,
which created the object.
Pressure change in the gaseous environment, in addition to creating the forces pushing (gravity) and generates energy in a given volume of ether. This pattern is represented by the equation Mendeleev-Clapeyron. E = 3/2 PVt (1), where E - Energy, P - Pressure, Vt - volume of ether’s torsion. We will suppose that atoms are created ether’s mikro torsion. Orbital speed of rotation of ether in mikro torsion decreases to direction from a center to periphery by law of reverse square. On the basis of principle of Bernoulli of pressure in ether of micro torsion changes inversely proportional to speed of rotation of ether on the examined orbit. Consider the model of the atom in (Figure 1). Around the nucleus of the atom radius r1 rotates broadcast. Density of the nucleus of an atom is so large that air cannot penetrate it. Consequently, the surface of the core is lower barrier to rotation of the ether in torsion. Velocity v1 - the maximum, the orbital velocity of the ether. The pressure in the volume of gaseous medium depends on density of the medium and its speed – v1. According to the theory of vortex gravitation . Pressure is the orbital speed of ether the following relationship.
The density of ether, an indication, according to .V1 - linear orbital velocity of the ether at the surface of the nucleus. Substituting (2) into (1)
To determine the rate of ether flow v in atomic torsion bars assume that the force of gravity vortex has little effect on the periphery of the torsion bar, order F? ~ 10-4 m. Based on the theory of vortex gravitation  with a force of gravity and orbit radius of the order of atomic torsion R ~ 10-7 , the linear velocity of the ether should be v ~ 109. For the dependence of v ~ r-1/2, it is determined that the surface of the nucleus, at r ~ 10-15 linear velocity is v1 ~ 1013
F? - the force of gravity of the body 2 of the body 1
R - Radius of atomic torsion
r1 - radius of the nucleus of the atom 1
Substitute in equation (3) values of the following orders:
We obtain the energy of the order of:
To determine the energy in a certain volume of uranium of mass
m, it is necessary to multiply the amount of energy of one atom
determined by formula (4) by the number of atoms in this volume.
The number of atoms is determined as the ratio of the mass of the
substance to the mass of one atom ~ 10-25.
Let us determine the energy in a body of mass m:
Based on the formula of Poincare define the order of the energy of the uranium atom in its mass
Consequently, the value of one atomic energy torsion theory
calculations of the vortex gravitation (Formula 3), corresponds to
the energy of the atom defined by the classical, experimental
formula. In the theory of vortex gravitation  that the
gravitational torsion create body. That is, the mass of any celestial
body depends on the speed of rotation of the corresponding
torsion. This statement is valid for the mass of a particle of air
speed in the corresponding micro torsion. Thus, on the basis of
the theory of gravity vortex can conclude - the energy and mass of
one body created by the same process - gravitational torsion. We
can therefore say that the mass of a body (atom) does not create
the energy of the body (an atom). To the extent it can be argued
that the energy of the body does not produce mass. These physical
properties of a body are each only an indirect relationship, as they
are generated by the same rotation of the vortex ether. At fracture
(splitting) of the atom (nucleus) breaks down and the nuclear
torsion. The pressure in the torsion increases sharply to values of
free ether, which should be accompanied by a release of energy,
according to the formula (3).